Construct the magnetic field pattern around the current carrying wires
Which description fits?
Around a current carrying wire, a magnetic field is ...
The direction of the magnetic field ...
The magnetic field between two poles is directed from ...
opposite poles ...
On the right side of the wire, both magnetic fields interact ...
The direction of force is towards the ...
All you need is a bar magnet, acrylic glass and iron fillings.
Before you put the iron fillings on the bar magnet put a acrylic glass in between.
Hint: make a video of the experiment.
How does the magnetic field pattern look like?
Where is the field homogeneous and where inhomogenous?
Does the direction change if we flip the manget?
Add a second bar magnet and repeat the experiement.
magnetic field pattern of a horse shoe magnet:
Calculate the magnetic flux density
magnetic flux density:
$B=\frac{\mu_0I}{2\pi r}=1.6 \cdot 10^{-5}~T$
distance from the wire:
$r=\frac{\mu_0I}{2\pi B}=2~cm$
magnetic flux density:
$B=\mu_0 n I = \mu_0 \frac{4800}{0.12} I = 0.126~T$
Construct the resulting magnetic field and force
magnetic field (blue) to the right, current (red) into the board
magnetic field (blue) and current (red) to the right
magnetic field (blue) into the board, current (red) to the right
magnetic field (blue), current (red) upwards
Resuslting magnetic field and force:
An electron with a charge of $Q=e=-1.6 \cdot 10^{-19}~As$ is moving with $v=5 \cdot 10^{7}~m/s$ perpendicular to an uniform magnetic field with flux density $B=6.25 \cdot 10^{-2}~T$. The mass of the electron is $m=9.1 \cdot 10^{-31}~kg$.
Resuslting magnetic field and force:
magnetic force:
$F=BQv= -5 \cdot 10^{-13}~N$
radius:
$r=\frac{mv}{BQ}= 4.55 \cdot 10^{-3}~m$
time period:
$T=\frac{2\pi m}{BQ}= 5.72 \cdot 10^{-10}~s$